Exams › NEET › Physics

Bunty mixed 440 gm of ice at \( 0^{\circ} \mathrm{C} \) with \( 540 \mathrm{gm} \) of water at \( 80^{\circ} \mathrm{C} \) in a bowl. Then what would remain after sometime in the bowl?

1. only ice
2. only water
3. ice and water in same amount
4. ice and water will vapourise

Correct answer: only water

Solution

The 540 g of water cooling from 80°C to 0°C releases enough heat to melt all 440 g of ice at 0°C. Since the ice fully melts and the final mixture is above 0°C, only water remains.

Related NEET Physics questions

• An instrument used to measure high temperature is
• Ocean currents are caused by the setting up of in water
• For the same mass, which one of the following has the maximum thermal capacity?
• The excess temperature of a body falls from \( 12^{\circ} \mathrm{C} \) to \( 6^{\circ} \mathrm{C} \) in 5 minutes, then the time to fall the excess temperature from \( 6^{\circ} \mathrm{C} \) to \( 3^{\circ} \mathrm{C} \) is (assume the Newton's cooling is valid)
• Mercury boils at \( 356^{\circ} \mathrm{C} \). However mercury thermometers are made such that they can measure temperatures up to \( 500^{\circ} \mathrm{C} \). This is done by :
• Name the process associated with the following. Dry ice is kept at room temperature and at one atmospheric pressure.

⚔️ Practice NEET Physics free + battle 1v1 →