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A deep rectangular pond of surface area A, containing water (density = ρ), specific heat (capacity = s), is located in a region where the outside air temperature is at a steady value of −26°C. The thickness of the frozen ice layer in this pond, at a certain instant is x. Taking the thermal conductivity of ice as K, and its specific latent heat of fusion as L, the rate of increase of the thickness of ice layer at this instant, would be given by

  1. 26K/ρx(L + 4s)
  2. 26K/ρx(L − 4s)
  3. 26K/(ρx2L)
  4. 26K/(ρxL)

Correct answer: 26K/(ρxL)

Solution

The rate of increase of the ice layer thickness is determined by the heat transfer through the ice layer due to the temperature difference. Using the concept of thermal conductivity and latent heat, the correct expression is derived as 26K/(ρxL).

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