Exams › NEET › Physics

Terminal velocity Vₜ = (ρ - σ)g. Vₜ₁ = 2 × (1)² / 9η (ρ₁ - 0.1ρ₂)g. Vₜ₂ = 2 × (2)² / 9η (ρ₂ - 0.1ρ₂)g. Vₜ₃ = 2 × (2)² / 9η (ρ₂ - 0.1ρ₂)g. Vₜ₁ / Vₜ₂ = 7.9 / 36.

1. Vₜ₁ = 2 × (1)² / 9η (ρ₁ - 0.1ρ₂)g
2. Vₜ₂ = 2 × (2)² / 9η (ρ₂ - 0.1ρ₂)g
3. Vₜ₃ = 2 × (2)² / 9η (ρ₂ - 0.1ρ₂)g
4. Vₜ₁ / Vₜ₂ = 7.9 / 36

Correct answer: Vₜ₁ / Vₜ₂ = 7.9 / 36

Solution

The given ratio Vₜ₁ / Vₜ₂ = 7.9 / 36 is explicitly stated in the question, making option D correct. The other options are equations that are already provided in the question and do not represent the final answer.

Related NEET Physics questions

• If the air density were uniform, then the height of the atmosphere above the sea level to produce a normal atmospheric pressure of \( 1.0 \times 10^{5} \) Pa is (density of air is \( 1.3 \mathrm{kg} / \mathrm{m}^{3}, \mathrm{g}=10 \mathrm{m} / \mathrm{s}^{2} \) ):
• 1atm \( = \)
• The atmospheric pressure at is 100,000 pascal.
• According to Newton, the viscous force acting between liquid layers of area A and velocity gradient ΔV/ΔZ is given by \( F = -ηA \frac{ΔV}{ΔZ} \) where η is constant called coefficient of viscosity. The dimensional formula of η is
• As we know that, surface tension(s) is:
• The cylindrical tube of a spray pump has radius, R, one end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is:

⚔️ Practice NEET Physics free + battle 1v1 →