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1atm \( = \)
- \( 100 \mathrm{cm} \) of \( \mathrm{Hg} \)
- \( 76 \mathrm{cm} \) of \( \mathrm{Hg} \)
- \( 20 \mathrm{cm} \) of \( \mathrm{Hg} \)
- \( 25 \mathrm{cm} \) of \( \mathrm{Hg} \)
Correct answer: \( 76 \mathrm{cm} \) of \( \mathrm{Hg} \)
Solution
One atmosphere is defined as the pressure exerted by a mercury column of about 76 cm at standard conditions. So the correct equivalence is 76 cm of Hg.
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