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We know that effective gravity g' at depth below earth surface is given by g' = g(1 - d/R). Here, d = 100 km, R = 6400 km. Calculate g'.
- 9.65 m/s²
- 9.8 m/s²
- 9.75 m/s²
- 9.85 m/s²
Correct answer: 9.65 m/s²
Solution
The formula for effective gravity at a depth is g' = g(1 - d/R). Substituting d = 100 km, R = 6400 km, and g = 9.8 m/s², we get g' = 9.8(1 - 100/6400) = 9.8(1 - 0.015625) = 9.8 × 0.984375 ≈ 9.65 m/s².
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