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A wheel of radius 1m rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially in contact with the ground is:

  1. 0
  2. π
  3. √π² + 4

Correct answer: √π² + 4

Solution

When the wheel rolls forward half a revolution, the point initially in contact with the ground moves to the topmost position of the wheel. The displacement is the straight-line distance between these two points, which forms the hypotenuse of a right triangle with sides of length 1m (radius). Using the Pythagorean theorem, the displacement is √(π² + 4).

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