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For same KE, momentum ∝ √m. Hence, the ratio is 2:1.

1. K1/K2 = p1²/m1 × m2/p2²
2. p = mv => K = p²/2m
3. p1/p2 = √M1/M2 = √1/4 = 1/2
4. Given force F = 2î + 3ĵ

Correct answer: p = mv => K = p²/2m

Solution

The relationship between kinetic energy (K) and momentum (p) is given by K = p²/2m. This directly matches option B.

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