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W = ΔE = 1/2 m(v₁² - v₂²). Find W for m = 1 kg, v₁ = 1000 m/s, v₂ = 500 m/s.

1. 3750 J
2. 2500 J
3. 5000 J
4. 1250 J

Correct answer: 5000 J

Solution

Using the work-energy theorem, W = 1/2 * m * (v₁² - v₂²). Substituting m = 1 kg, v₁ = 1000 m/s, and v₂ = 500 m/s, we get W = 1/2 * 1 * (1000² - 500²) = 1/2 * (1000000 - 250000) = 1/2 * 750000 = 375000 J. Thus, W = 3750 J.

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