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ExamsNEETPhysics

Work done against gravity = mg sin θ × d (d sin θ = 10)

  1. 200 J
  2. 100 J
  3. 300 J
  4. 400 J

Correct answer: 100 J

Solution

The work done against gravity is given by W = m * g * h, where h is the vertical height. From the question, d * sin θ = 10, so h = 10. Assuming g = 10 m/s² and m = 1 kg (not explicitly given but implied for simplicity), W = 1 * 10 * 10 = 100 J.

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