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A bomb of mass 30 kg at rest explodes into two pieces of masses 18 kg and 12 kg. The velocity of 18 kg mass is 6 m/s. The kinetic energy of the other mass is:

1. 324 J
2. 486 J
3. 256 J
4. 524 J

Correct answer: 486 J

Solution

By conservation of momentum, the velocity of the 12 kg mass is calculated as \( v = \frac{18 \times 6}{12} = 9 \, \text{m/s} \). The kinetic energy of the 12 kg mass is \( KE = \frac{1}{2} m v^2 = \frac{1}{2} \times 12 \times 9^2 = 486 \; \text{J} \).

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