Exams › NEET › Physics

A metal ball of mass 2 kg moving with a velocity of 36 km/h has a head on collision with a stationary ball of mass 3 kg. If after the collision, the two balls move together, the loss in kinetic energy due to collision is

1. 140 J
2. 100 J
3. 60 J
4. 40 J

Correct answer: 140 J

Solution

The initial kinetic energy of the system is due to the moving 2 kg ball: KE_initial = (1/2) * 2 * (10)^2 = 100 J (converting 36 km/h to 10 m/s). After the collision, the combined mass (5 kg) moves with velocity v = (2 * 10) / (2 + 3) = 4 m/s. The final kinetic energy is KE_final = (1/2) * 5 * (4)^2 = 40 J. The loss in kinetic energy is KE_initial - KE_final = 100 - 40 = 60 J.

Related NEET Physics questions

• Assertion A load when lifted vertically up requires greater effort than to roll the same load up the ramp. Reason The work done in lifting the load vertically up is less.
• The graph between the resistive force acting on a body and the position of the body travelling in a straight line is shown in the figure. The mass of the body is \( 25 \mathrm{kg} \) and initial velocity is 2 m/s.When the distance covered by the bodyi \( s 4 \mathrm{m}, \) its kinetic energy would be
• Potential energy increases with the increase in :
• Three different objects of masses m1, m2, and m3 are allowed to fall from rest and from the same point O along three different frictionless paths. The speeds of the three objects on reaching the ground will be in the ratio of
• What is the minimum velocity with which a body of mass m must enter a vertical loop of radius R so that it can complete the loop?
• A particle of mass m₁ is moving with a velocity v₁ and another particle of mass m₂ is moving with a velocity v₂. Both of them have the same momentum but their different kinetic energies are E₁ and E₂ respectively. If m₁ > m₂ then:

⚔️ Practice NEET Physics free + battle 1v1 →