Exams › NEET › Physics

Two spheres A and B of masses m₁ and m₂ respectively collide. A is at rest initially and B is moving with velocity v along x-axis. After collision B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction:

1. Same as that of B
2. Opposite to that of B
3. θ = tan⁻¹(1/2) to the x-axis
4. θ = tan⁻¹(-1/2) to the x-axis

Correct answer: θ = tan⁻¹(1/2) to the x-axis

Solution

Using the principle of conservation of momentum in both x and y directions, the direction of A's motion after collision is determined to be θ = tan⁻¹(1/2) to the x-axis.

Related NEET Physics questions

• Assertion A load when lifted vertically up requires greater effort than to roll the same load up the ramp. Reason The work done in lifting the load vertically up is less.
• The graph between the resistive force acting on a body and the position of the body travelling in a straight line is shown in the figure. The mass of the body is \( 25 \mathrm{kg} \) and initial velocity is 2 m/s.When the distance covered by the bodyi \( s 4 \mathrm{m}, \) its kinetic energy would be
• Potential energy increases with the increase in :
• Three different objects of masses m1, m2, and m3 are allowed to fall from rest and from the same point O along three different frictionless paths. The speeds of the three objects on reaching the ground will be in the ratio of
• What is the minimum velocity with which a body of mass m must enter a vertical loop of radius R so that it can complete the loop?
• A particle of mass m₁ is moving with a velocity v₁ and another particle of mass m₂ is moving with a velocity v₂. Both of them have the same momentum but their different kinetic energies are E₁ and E₂ respectively. If m₁ > m₂ then:

⚔️ Practice NEET Physics free + battle 1v1 →