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A ball is thrown vertically downwards from a height of 20 m with an initial velocity v₀. It collides with the ground, loses 50 percent of its energy in collision, and rebounds to the same height. The initial velocity v₀ is: (Take g = 10 m/s²)
- 20 m/s
- 28 m/s
- 10 m/s
- 14 m/s
Correct answer: 28 m/s
Solution
The ball loses 50% of its energy during collision but still rebounds to the same height, implying its initial kinetic energy must compensate for the energy loss. Using energy conservation and solving for v₀, we find it to be 28 m/s.
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