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On a frictionless surface a block of mass M moving at speed v collides elastically with another block of same mass M which is initially at rest. After collision the first block moves at an angle θ to its initial direction and has a speed

1. v/2
2. v/√2
3. v
4. √2v

Correct answer: v/√2

Solution

In an elastic collision between two identical masses, where one is initially at rest, the velocities after collision are such that the first block moves at an angle θ with speed v/√2, and the second block moves at the complementary angle with the same speed. This follows from conservation of momentum and kinetic energy.

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