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A moving block having mass m₁ collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will be

1. 0.5
2. 0.25
3. 0.4
4. 0.8

Correct answer: 0.5

Solution

The coefficient of restitution (e) is defined as the ratio of relative velocity of separation to relative velocity of approach. Since the lighter block comes to rest after collision, the velocity of the heavier block can be calculated using momentum conservation. Substituting the values, e = 0.5.

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