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Two bodies of masses m and 4m are moving with equal kinetic energies. The ratio of their linear momenta will be

1. 1 : 4
2. 4 : 1
3. 1 : 2
4. 2 : 1

Correct answer: 2 : 1

Solution

Kinetic energy is given by KE = p²/2m, where p is momentum. For equal KE, p ∝ √m. Thus, the ratio of their momenta is √m : √(4m) = 1 : 2.

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