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A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s²)

1. 30 J
2. 40 J
3. 10 J
4. 20 J

Correct answer: 30 J

Solution

The initial kinetic energy is (1/2)mv² = (1/2)(1)(20²) = 200 J. The potential energy at the maximum height is mgh = (1)(10)(18) = 180 J. The energy lost due to air friction is the difference: 200 J - 180 J = 30 J.

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