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A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to 8 × 10⁻⁴ J by the end of the second revolution after the beginning of the motion?

1. 0.1 m/s²
2. 0.15 m/s²
3. 0.18 m/s²
4. 0.2 m/s²

Correct answer: 0.15 m/s²

Solution

The work-energy theorem states that the work done by the tangential force equals the change in kinetic energy. Using the relation for tangential acceleration and the distance covered in two revolutions (2 × 2πr), we calculate the tangential acceleration as 0.15 m/s².

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