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A force F acting on an object varies with distance x as shown here. The force is in N and x in m. The work done by the force in moving the object from x = 0 to x = 6 m is
- 18.0 J
- 13.5 J
- 9.0 J
- 4.5 J
Correct answer: 13.5 J
Solution
The work done by a variable force is the area under the force vs. distance graph. Here, the graph forms a triangle with base 6 m and height 4.5 N. The area is (1/2) × base × height = (1/2) × 6 × 4.5 = 13.5 J.
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