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ExamsNEETPhysics

A force F acting on an object varies with distance x as shown here. The force is in N and x in m. The work done by the force in moving the object from x = 0 to x = 6 m is

  1. 18.0 J
  2. 13.5 J
  3. 9.0 J
  4. 4.5 J

Correct answer: 13.5 J

Solution

The work done by a variable force is the area under the force vs. distance graph. Here, the graph forms a triangle with base 6 m and height 4.5 N. The area is (1/2) × base × height = (1/2) × 6 × 4.5 = 13.5 J.

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