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300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g = 10 m/s², work done against friction is

1. 100 J
2. zero
3. 1000 J
4. 200 J

Correct answer: 100 J

Solution

The work done against gravity is mgh = 2 × 10 × 10 = 200 J. Since the total work done is 300 J, the work done against friction is 300 - 200 = 100 J.

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