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Two similar springs P and Q have spring constants KP and KQ, such that KP > KQ. They are stretched, first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ are related as, in case (a) and case (b), respectively:

1. WP = WQ ; WP = WQ
2. WP > WQ ; WQ > WP
3. WP < WQ ; WP > WQ
4. WP > WQ ; WP > WQ

Correct answer: WP > WQ ; WQ > WP

Solution

In case (a), work done is proportional to the spring constant when stretched by the same amount, so WP > WQ. In case (b), work done is inversely proportional to the spring constant when stretched by the same force, so WQ > WP.

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