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Velocity of the rocket (u) = 300 m/s and force (F) = 345 N. According to Newton's second law, thrust (force) = Rate of change of linear momentum. Calculate the thrust.

1. 1.15 kg/s
2. 3.45 kg/s
3. 0.3 kg/s
4. 2.15 kg/s

Correct answer: 3.45 kg/s

Solution

Thrust is given by F = dp/dt = u * (dm/dt), where dm/dt is the rate of mass ejection. Rearranging, dm/dt = F/u = 345/300 = 1.15 kg/s.

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