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A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is:
- MV
- 1.5 MV
- 2 MV
- zero
Correct answer: 2 MV
Solution
Impulse is the change in momentum. The initial momentum is MV (towards the wall), and the final momentum is -MV (away from the wall). The change in momentum is (-MV) - (MV) = -2MV. The magnitude of impulse is 2MV.
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