A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:

the mass is at the highest point of the circle
the mass is at the lowest point of the circle
the wire is horizontal
the mass is at an angle of 45° from the vertical

Correct answer: the mass is at the lowest point of the circle

Solution

The tension in the wire is maximum at the lowest point of the circle because it has to support both the weight of the mass and provide the centripetal force for circular motion. This makes the wire most likely to break at this point.

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