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A block has been placed on an inclined plane with the slope angle θ. Block slides down the plane at constant speed. The coefficient of kinetic friction is equal to:

1. sin θ
2. cos θ
3. g
4. tan θ

Correct answer: tan θ

Solution

For the block to slide at constant speed, the net force along the incline must be zero. This implies that the component of gravitational force along the incline (mg sin θ) is balanced by the kinetic friction force (μk mg cos θ). Solving for μk, we get μk = tan θ.

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