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A man weighing 80 kg stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5 m/s². What would be the reading on the scale? (g = 10 m/s²)

1. 1200N
2. zero
3. 400N
4. 800N

Correct answer: 1200N

Solution

The apparent weight of the man is given by the normal force, which equals m(g + a) when the lift accelerates upwards. Substituting m = 80 kg, g = 10 m/s², and a = 5 m/s², we get N = 80(10 + 5) = 1200 N.

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