Exams › NEET › Physics

Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is:

1. g/2
2. g/5
3. g/10
4. g

Correct answer: g/5

Solution

The net force acting on the system is due to the difference in weights of the two masses. Using Newton's second law, the acceleration is calculated as a = (m2 - m1)g / (m1 + m2). Substituting m1 = 4 kg and m2 = 6 kg, we get a = (6 - 4)g / (6 + 4) = 2g / 10 = g/5.

Related NEET Physics questions

• Conservation of momentum in a collision between particles can be understood from
• Assertion (A): According to Newton's third law sum of action and reaction is not equal to zero Reason (R) : The forces action and reaction acts on different bodies.
• Who proposed the concept of Inertia?
• Which of the following Newton's law(s) is/are not applicable in non-inertial reference frame.
• Assertion When a bus starts suddenly, a person standing in it falls backwards. Reason It is due to inertia of rest.
• A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is:

⚔️ Practice NEET Physics free + battle 1v1 →