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If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is

1. 0.55 kg/sec
2. 0.75 kg/sec
3. 1.15 kg/sec
4. 2.25 kg/sec

Correct answer: 0.55 kg/sec

Solution

The force on the rocket is given by F = v(dm/dt), where v is the velocity and dm/dt is the rate of combustion of fuel. Rearranging, dm/dt = F/v = 345/300 = 1.15 kg/sec.

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