Exams › NEET › Physics

If the force acting on a particle is always perpendicular to the velocity of the particle, then the path of the particle is a circle. The centripetal force (F) is always perpendicular to the velocity of the particle, i.e., F ⊥ v.

1. W = mg ΔK
2. m² = m(u² − 2gℓ)
3. v² = u² − 2gℓ
4. v = √[u² − 2gℓ]

Correct answer: v² = u² − 2gℓ

Solution

The correct equation for motion under constant acceleration (like gravity) is v² = u² − 2gℓ, which relates the final velocity, initial velocity, acceleration, and displacement. This matches the scenario described.

Related NEET Physics questions

• In the equation of motion, \( \boldsymbol{S}=\boldsymbol{u} \boldsymbol{t}+ \) \( 1 / 2 a t^{2}, \) S stands for
• A body is accelerated by applying a force of 30 N. The change in the momentum of the body after 2 sec is?
• A passenger in moving train tosses a coin which falls behind him. It means that the motion of the train is
• From the displacement-time graph shown here, find the velocity of the body as it moves from \( A \) to \( B \)
• The distance of a particle as a function of time is shown below. The graph indicates that
• Whenever an object moves with a constant speed, its distance - time graph is a

⚔️ Practice NEET Physics free + battle 1v1 →