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Speed of the bullet (v) = 1000 m/s and horizontal distance of the target (s) = 100 m. Time taken to cover the horizontal distance (t) = 100/1000 = 0.1 sec. During this time, the bullet will fall down vertically due to gravitational acceleration. ∴ height (h) = 1/2 gt^2.
- (a) Speed of the bullet (v) = 1000 m/s and horizontal distance of the target (s) = 100 m
- (b) Time taken to cover the horizontal distance (t) = 100/1000 = 0.1 sec
- (c) During this time, the bullet will fall down vertically due to gravitational acceleration
- (d) ∴ height (h) = 1/2 gt^2
Correct answer: (d) ∴ height (h) = 1/2 gt^2
Solution
The correct answer is (d) because the height (h) is calculated using the formula for vertical displacement under constant acceleration, h = 1/2 gt^2, which is derived from the equations of motion.
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