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A particle moves along a circle of radius (20/π) m with constant tangential acceleration. If the velocity of the particle is 80 m/s at the end of the second revolution after motion has begun, the tangential acceleration is

1. 40 m/s²
2. 80 m/s²
3. 640 m/s²
4. 160 m/s²

Correct answer: 40 m/s²

Solution

The total distance covered in two revolutions is the circumference multiplied by 2, which is 40 m. Using the equation of motion, v² = u² + 2as, where u = 0, v = 80 m/s, and s = 40 m, we solve for a: a = v² / (2s) = 80² / (2 × 40) = 40 m/s².

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