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A particle moves in a circle of radius 5 cm with constant speed and time period 0.2 s. The acceleration of the particle is

1. 15 m/s²
2. 25 m/s²
3. 36 m/s²
4. 5 m/s²

Correct answer: 25 m/s²

Solution

The centripetal acceleration is given by a = v²/r, where v = 2πr/T. Substituting r = 0.05 m and T = 0.2 s, we find v = 2π(0.05)/0.2 = 1.57 m/s. Then, a = (1.57)²/0.05 ≈ 25 m/s².

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