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If a body A of mass M is thrown with velocity v at an angle of 30° to the horizontal and another body B of the same mass is thrown with the same speed at an angle of 60° to the horizontal, the ratio of horizontal range of A to B will be
- 1:3
- 1:1
- 1:√3
- √3:1
Correct answer: 1:1
Solution
The horizontal range of a projectile is given by R = (v² sin(2θ)) / g. For both A and B, the speed v and g are the same. Since sin(2θ) = sin(60°) for both θ = 30° and θ = 60°, the ranges are equal, making the ratio 1:1.
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