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For angles of projection of a projectile (45° − θ) and (45° + θ), the horizontal ranges described by the projectile are in the ratio
- 1:3
- 1:2
- 2:1
- 1:1
Correct answer: 1:1
Solution
The horizontal range of a projectile depends on the angle of projection and is symmetric about 45°. For angles (45° − θ) and (45° + θ), the ranges are equal, resulting in a ratio of 1:1.
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