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The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectiles is:

1. θ = tan⁻¹(1/4)
2. θ = tan⁻¹(4)
3. θ = tan⁻¹(2)
4. θ = 45°

Correct answer: θ = tan⁻¹(2)

Solution

For a projectile, the horizontal range (R) and maximum height (H) are related by R = 4H * tan(θ). If R = H, then tan(θ) = 4, giving θ = tan⁻¹(4).

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