The velocity of a projectile at the initial point A is (2î + 3ĵ) m/s. Its velocity (in m/s) at point B is

-2î + 3ĵ
2î - 3ĵ
-2î - 3ĵ
2î + 3ĵ

Correct answer: 2î - 3ĵ

Solution

In projectile motion, the horizontal component of velocity remains constant, while the vertical component changes direction and sign due to gravity. At point B, the horizontal component remains +2 m/s, but the vertical component becomes -3 m/s, making the velocity 2î - 3ĵ.

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