A body of 3 kg moves in the XY plane under the action of a force given by 6t²î + 4tĵ. Assuming that the body is at rest at time t = 0, the velocity of the body at t = 3 s is

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18î + 12ĵ. The force is given as F = 6t²î + 4tĵ. Using Newton's second law, acceleration a = F/m = (6t²/3)î + (4t/3)ĵ = 2t²î + (4/3)tĵ. Integrating acceleration with respect to time gives velocity: v = ∫a dt = ∫(2t²î + (4/3)tĵ) dt = (2t³/3)î + (2t²/3)ĵ + C. Since the body is at rest at t = 0, C = 0. At t = 3 s, v = (2(3³)/3)î + (2(3²)/3)ĵ = 18î + 12ĵ.

A body of 3 kg moves in the XY plane under the action of a force given by 6t²î + 4tĵ. Assuming that the body is at rest at time t = 0, the velocity of the body at t = 3 s is

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