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A body constrained to move in y-direction, is subjected to a force given by F = (-2î + 15ĵ + 6k̂) N. What is the work done by this force in moving the body through a distance of 10 m along y-axis?

1. 190 J
2. 160 J
3. 150 J
4. 20 J

Correct answer: 150 J

Solution

Work done is given by the dot product of force and displacement. Since the body moves only along the y-axis, the displacement vector is 10ĵ. The dot product of F = (-2î + 15ĵ + 6k̂) and 10ĵ is (15 × 10) = 150 J.

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