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Equation of the motion of uniformly accelerated motion, the distance travelled in nth sec is given by Sn = u + a/2 (2n - 1).

1. S4 = 0 + a/2 (2×4 - 1) = 7
2. S3 = 0 + a/2 (2×3 - 1) = 5
3. In one dimensional motion, the body can have at a time one velocity but not two values of velocities.
4. Let PQ = x, then u = 30 km/h, v = 40 km/h, a = 40² - 30² / 2x = 350/x. Also, velocity at mid point is given by vm => vm² = u² + 2a(7).

Correct answer: S3 = 0 + a/2 (2×3 - 1) = 5

Solution

Option B correctly applies the formula for distance traveled in the nth second, Sn = u + a/2 (2n - 1), with u = 0, n = 3, and calculates S3 = 0 + a/2 (2×3 - 1) = 5. Other options either misapply the formula or are unrelated.

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