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Find the distance travelled by a particle in the nth second if its initial velocity is u and acceleration is a.

1. Distance travelled in nth second is Sn = u + a/2(2n - 1)
2. Given u = 0, a = 4/3 ms^-2, n = 3
3. Sn = 0 + (4/3 × 2 × 3 - 1) = 10/3 m
4. None of these

Correct answer: None of these

Solution

The formula for distance traveled in the nth second is Sn = u + a/2(2n - 1). However, the calculation in option C is incorrect. The correct calculation should be Sn = u + a/2(2n - 1) = 0 + (4/3) × (2 × 3 - 1) = 0 + (4/3) × 5 = 20/3 m, which is not listed in the options.

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