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An object is thrown vertically upward with an initial velocity u = 10 ms^-1. Find the time taken to reach the maximum height if the acceleration due to gravity is g = 9 ms^-2.

1. Initial velocity, u = 10 ms^-1
2. Final velocity, v = 0
3. Acceleration, a = -g = -9 ms^-2
4. Time taken, t = u/a = 10/9 seconds

Correct answer: Time taken, t = u/a = 10/9 seconds

Solution

The time to reach maximum height is calculated using the equation v = u + at. At maximum height, v = 0, so t = -u/a = 10/9 seconds. The negative sign of acceleration indicates it opposes the motion.

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