Exams › NEET › Physics

A ball is thrown vertically upward. It has a speed of 10 m/sec when it has reached one half of its maximum height. How high does the ball rise? Take g = 10 m/s².

1. 10 m
2. 5 m
3. 15 m
4. 20 m

Correct answer: 10 m

Solution

At half the maximum height, the velocity is given as 10 m/s. Using the energy conservation principle, the total mechanical energy remains constant. The maximum height can be calculated using the relation: h = v² / (2g), where v is the initial velocity at the bottom. Substituting v = 10 m/s and g = 10 m/s², we get h = 10 m.

Related NEET Physics questions

• Assertion A load when lifted vertically up requires greater effort than to roll the same load up the ramp. Reason The work done in lifting the load vertically up is less.
• The graph between the resistive force acting on a body and the position of the body travelling in a straight line is shown in the figure. The mass of the body is \( 25 \mathrm{kg} \) and initial velocity is 2 m/s.When the distance covered by the bodyi \( s 4 \mathrm{m}, \) its kinetic energy would be
• Potential energy increases with the increase in :
• Three different objects of masses m1, m2, and m3 are allowed to fall from rest and from the same point O along three different frictionless paths. The speeds of the three objects on reaching the ground will be in the ratio of
• What is the minimum velocity with which a body of mass m must enter a vertical loop of radius R so that it can complete the loop?
• A particle of mass m₁ is moving with a velocity v₁ and another particle of mass m₂ is moving with a velocity v₂. Both of them have the same momentum but their different kinetic energies are E₁ and E₂ respectively. If m₁ > m₂ then:

⚔️ Practice NEET Physics free + battle 1v1 →