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A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 m/s², the velocity with which it hits the ground is

1. 10.0 m/s
2. 20.0 m/s
3. 40.0 m/s
4. 5.0 m/s

Correct answer: 20.0 m/s

Solution

The stone falls freely under gravity, so we use the equation of motion: v = √(2gh). Substituting g = 10 m/s² and h = 20 m, we get v = √(2 × 10 × 20) = √400 = 20 m/s.

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