Exams › NEET › Physics

The displacement of a particle is represented by the following equation: s = 3t³ + 7t² + 5t + 8 where s is in metre and t in second. The acceleration of the particle at t = 1 is:

1. 14 m/s²
2. 18 m/s²
3. 32 m/s²
4. zero

Correct answer: 18 m/s²

Solution

To find acceleration, we first differentiate the displacement equation twice with respect to time. The first derivative gives velocity: v = ds/dt = 9t² + 14t + 5. The second derivative gives acceleration: a = dv/dt = 18t + 14. Substituting t = 1, a = 18(1) + 14 = 18 m/s².

Related NEET Physics questions

• In the equation of motion, \( \boldsymbol{S}=\boldsymbol{u} \boldsymbol{t}+ \) \( 1 / 2 a t^{2}, \) S stands for
• A body is accelerated by applying a force of 30 N. The change in the momentum of the body after 2 sec is?
• A passenger in moving train tosses a coin which falls behind him. It means that the motion of the train is
• From the displacement-time graph shown here, find the velocity of the body as it moves from \( A \) to \( B \)
• The distance of a particle as a function of time is shown below. The graph indicates that
• Whenever an object moves with a constant speed, its distance - time graph is a

⚔️ Practice NEET Physics free + battle 1v1 →