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The position x of a particle with respect to time t along y-axis is given by x = 9t² − t³ where x is in metres and t in second. What will be the position of this particle when it achieves maximum speed along the +ve x direction?
- 54m
- 81m
- 24m
- 32m
Correct answer: 54m
Solution
To find the maximum speed, we calculate the velocity v = dx/dt = 18t - 3t². Setting dv/dt = 0 for maximum, we get 18 - 6t = 0, which gives t = 3s. Substituting t = 3s into x = 9t² - t³, we get x = 9(3)² - (3)³ = 81 - 27 = 54m.
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