A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S₁ and that covered in the first 20 seconds is S₂, then:

Question

Accepted Answer

S₂ = 3S₁. The particle starts from rest under constant acceleration. Using the equation of motion, S = (1/2)at², the distance covered in 10 seconds is proportional to 10², and in 20 seconds to 20². Thus, S₂/S₁ = (20²)/(10²) = 4, so S₂ = 4S₁.

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S₁ and that covered in the first 20 seconds is S₂, then:

Solution

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