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A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is:

1. 1 m/s²
2. 7 m/s²
3. 7√2 m/s²
4. 5 m/s²

Correct answer: 5 m/s²

Solution

The initial velocity is 30 m/s east, and the final velocity is 40 m/s north. The change in velocity is the vector difference, which forms a right triangle with sides 30 m/s and 40 m/s. The magnitude of the change in velocity is √(30² + 40²) = 50 m/s. Average acceleration is change in velocity divided by time: 50/10 = 5 m/s².

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