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A particle has initial velocity (3î + 4ĵ) and has acceleration (0.4î + 0.3ĵ). Its speed after 10s is:

1. 7 units
2. 7√2 units
3. 8.5 units
4. 10 units

Correct answer: 7 units

Solution

The final velocity is calculated using the formula v = u + at. Substituting the given values, v = (3î + 4ĵ) + 10(0.4î + 0.3ĵ) = (7î + 7ĵ). The speed is the magnitude of the velocity vector, √(7² + 7²) = 7√2 units.

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