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A particle has initial velocity (2î + 3ĵ) and acceleration (0.3î + 0.2ĵ). The magnitude of velocity after 10 seconds will be:

1. 9√2 units
2. 5√2 units
3. 5 units
4. 9 units

Correct answer: 5√2 units

Solution

The velocity after time t is given by v = u + at. Substituting u = (2î + 3ĵ), a = (0.3î + 0.2ĵ), and t = 10 s, we get v = (2 + 0.3×10)î + (3 + 0.2×10)ĵ = (5î + 5ĵ). The magnitude of velocity is |v| = √(5² + 5²) = 5√2 units.

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