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(μ₀ε₀)⁻¹/² = 1/√μ₀ε₀ => c = speed of light where ε₀ = permittivity of free space, μ₀ = permeability of free space. So dimensions of (μ₀ε₀)⁻¹/² will be [LT⁻¹].

1. Force = mass × acceleration
2. Work = Force × displacement
3. (μ₀ε₀)⁻¹/² = 1/√μ₀ε₀ => c = speed of light
4. Torque = Force × force arm

Correct answer: (μ₀ε₀)⁻¹/² = 1/√μ₀ε₀ => c = speed of light

Solution

The equation (μ₀ε₀)⁻¹/² = c relates the permeability and permittivity of free space to the speed of light. The dimensions of (μ₀ε₀)⁻¹/² are indeed [LT⁻¹], which matches the dimensions of speed.

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